As we go from the equator of the earth to pole of the earth, the value of acceleration due to gravity (a) decreases (b) decreases up to latitude of 45° and increases thereafter (c) remains same (d) increases

Answer: (d). g' = g - ω² Rcos ²λ; cos λ falls from 1 at the equator to 0 at the pole. Also the polar radius is smaller than the equatorial radius, which raises g at the poles. So the answer is (d) g increases.

As we go from the equator of the earth to pole of the earth, the… | MHT CET 2020 (16 Oct, Shift 2)

Q103MHT CET 2020 · 16 OCT · SHIFT 2Easy

Acceleration Due to Gravity

As we go from the equator of the earth to pole of the earth, the value of acceleration due to gravity

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Answer: (d)

$g' = g - \omega^2 R\cos^2\lambda$ ; $\cos\lambda$ falls from 1 at the equator to 0 at the pole.
Also the polar radius is smaller than the equatorial radius, which raises $g$ at the poles.
So the answer is (d) $g$ increases.

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