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MHT CET 2021 (24 Sep, Shift 2) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2021 (24 Sep, Shift 2)

Q90MHT CET 2021 · 24 SEP · SHIFT 2Easy

Thermal Radiation: Black Body, Stefan & Wien

Assume that for solar radiation, surface temperature of the sun is 6000 K6000\text{ K}. If Wien's constant 'b' is 2.897×10−3 mK2.897 \times 10^{-3}\text{ mK}, the value of maximum wavelength will be

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Answer: (a)

  1. Wien's law: λm=bT\lambda_m = \dfrac{b}{T}.
  2. λm=2.897×10−36000=4.828×10−7 m\lambda_m = \dfrac{2.897 \times 10^{-3}}{6000} = 4.828 \times 10^{-7}\ \text{m}
  3. =4828 A˚= 4828\ \mathring{A}
  4. So the answer is (a) 4828 A˚4828\ \mathring{A}.
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