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MHT CET 2025 (22 Apr, Shift 1) · Resolving Power

Resolving Power question from MHT CET 2025 (22 Apr, Shift 1)

Q9MHT CET 2025 · 22 APR · SHIFT 1Medium

Resolving Power

Assuming human pupil to have radius of 0.25 cm and comfortable viewing distance of 25 cm, the minimum separation between the two objects that human eye can resolve at 500 nm wavelength is nearly

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Answer: (b)

  1. Pupil diameter D=0.5D = 0.5 cm =5×10−3= 5\times10^{-3} m.
  2. θ=1.22λD=1.22×500×10−95×10−3=1.22×10−4\theta = \dfrac{1.22\lambda}{D} = \dfrac{1.22\times500\times10^{-9}}{5\times10^{-3}} = 1.22\times10^{-4} rad
  3. x=d θ=0.25×1.22×10−4=3.05×10−5x = d\,\theta = 0.25 \times 1.22\times10^{-4} = 3.05\times10^{-5} m
  4. So the answer is (b) 30 μ30\ \mum.
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