Assuming in forward bias condition there is a voltage drop of 0.7 V across a silicon diode, the current through diode D₁ in the circuit is ______ mA. (Assume all diodes in the given circuit are identical) (a) 17.6 (b) 18.8 (c) 20.15 (d) 11.7

Answer: (b). D₁ and D₃ point down (forward biased); D₂ points up (reverse biased, no current). The conducting diodes are in parallel, so the voltage across them is 0.7 V. Current through R₁: I = (12 - 0.7)/(300) = (11.3)/(300) = 37.67 mA Identical diodes share it equally: ID₁ = (37.67)/(2) ≈ 18.8 mA So the answer is (b) 18.8 mA.

Assuming in forward bias condition there is a voltage drop of 0.7 V… | JEE Main 2026 (28 Jan, Shift 1)

Q18JEE Main 2026 · 28 JAN · SHIFT 1Medium

P-N Junction Diode

Assuming in forward bias condition there is a voltage drop of 0.7 V across a silicon diode, the current through diode $D_1$ in the circuit is ______ mA.

(Assume all diodes in the given circuit are identical)

Show answer and solution

Answer: (b)

$D_1$ and $D_3$ point down (forward biased); $D_2$ points up (reverse biased, no current).
The conducting diodes are in parallel, so the voltage across them is $0.7$ V.
Current through $R_1$ : $I = \dfrac{12 - 0.7}{300} = \dfrac{11.3}{300} = 37.67$ mA
Identical diodes share it equally: $I_{D_1} = \dfrac{37.67}{2} \approx 18.8$ mA
So the answer is (b) $18.8$ mA.

Report a mistake

P-N Junction Diode question from JEE Main 2026 (28 Jan, Shift 1)

More questions on P-N Junction Diode