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Gravitational Potential & Energy question from NEET 2019

Q24NEET 2019Medium

Gravitational Potential & Energy

Assuming that the gravitational potential energy of an object at infinity is zero, the change in potential energy (final $-$ initial) of an object of mass $m$ , when taken to a height $h$ from the surface of earth (of radius $R$ ), is given by,

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Answer: (c)

$U_i = -\frac{GMm}{R}$ , $U_f = -\frac{GMm}{R+h}$
$\Delta U = GMm\left(\frac{1}{R} - \frac{1}{R+h}\right) = \frac{GMmh}{R(R+h)}$
So the answer is (c).

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