Assuming the earth to be a sphere of uniform mass density, the weight of a body at a depth d = R/2 from the surface of earth, if its weight on the surface of earth is 200 N, will be: (Given R = radius of earth) (a) 100 N (b) 400 N (c) 300 N (d) 500 N

Answer: (a). Weight at depth: Wd = W(1 - d/R). d = R/2 ⇒ Wd = 200 × 1/2 So the answer is (a) 100 N.

Assuming the earth to be a sphere of uniform mass density, the weight… | JEE Main 2023 (10 Apr, Shift 1)

Q59JEE Main 2023 · 10 APR · SHIFT 1Easy

Acceleration Due to Gravity

Assuming the earth to be a sphere of uniform mass density, the weight of a body at a depth $d = \frac{R}{2}$ from the surface of earth, if its weight on the surface of earth is 200 N, will be:

(Given R = radius of earth)

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Answer: (a)

Weight at depth: $W_d = W\left(1 - \frac{d}{R}\right)$ .
$d = \frac{R}{2} \Rightarrow W_d = 200 \times \frac{1}{2}$
So the answer is (a) $100\text{ N}$ .

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