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JEE Main 2020 (6 Sep, Shift 2) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2020 (6 Sep, Shift 2)

Q115JEE Main 2020 · 6 SEP · SHIFT 2Medium

Matter Waves: de Broglie Wavelength

Assuming the nitrogen molecule is moving with r.m.s. velocity at 400 K, the de-Broglie wavelength of nitrogen molecule is close to:

(Given: nitrogen molecule weight: 4.64 ×\times 10–26 kg,

Boltzmann constant: 1.38 ×\times 10–23 J/K,

Planck constant: 6.63 ×\times 10–34 J.s)

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Answer: (d)

  1. vrms=3kT/m⇒p=3mkTv_{rms} = \sqrt{3kT/m} \Rightarrow p = \sqrt{3mkT}, λ=h3mkT\lambda = \dfrac{h}{\sqrt{3mkT}}.
  2. 3mkT=3×4.64×10−26×1.38×10−23×400≈7.68×10−463mkT = 3 \times 4.64 \times 10^{-26} \times 1.38 \times 10^{-23} \times 400 \approx 7.68 \times 10^{-46}, so 3mkT≈2.77×10−23\sqrt{3mkT} \approx 2.77 \times 10^{-23}
  3. λ=6.63×10−342.77×10−23≈2.4×10−11 m=0.24 A˚\lambda = \dfrac{6.63 \times 10^{-34}}{2.77 \times 10^{-23}} \approx 2.4 \times 10^{-11}\text{ m} = 0.24\ \mathring{A}
  4. So the answer is (d) 0.24 Å.
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