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MHT CET 2026 (14 May, Shift 1) · Gas Laws & Ideal Gas Equation

Gas Laws & Ideal Gas Equation question from MHT CET 2026 (14 May, Shift 1)

Q11MHT CET 2026 · 14 MAY · SHIFT 1Medium

Gas Laws & Ideal Gas Equation

At $10^\circ$ C, the value of density of a fixed mass of a gas (ideal) divided by its pressure is $x$ . At $110^\circ$ C this ratio is

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Answer: (d)

$P = \frac{\rho RT}{M} \Rightarrow \frac{\rho}{P} = \frac{M}{RT} \propto \frac{1}{T}$ .
$T_1 = 283\text{ K}$ , $T_2 = 383\text{ K}$ .
New ratio $= x\cdot\frac{283}{383}$ .
So the answer is (d) $\frac{283x}{383}$ .

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