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NEET 2008 (AIPMT) · Gas Laws & Ideal Gas Equation

Gas Laws & Ideal Gas Equation question from NEET 2008 (AIPMT)

Q79NEET 2008 · AIPMTMedium

Gas Laws & Ideal Gas Equation

At 10oC the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110oC this ratio is

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Answer: (b)

$\frac{\rho}{P} = \frac{M}{RT} \propto \frac{1}{T}$ .
$T_1 = 283\text{ K}$ , $T_2 = 383\text{ K}$ , so new ratio $= \frac{283}{383}x$ .
So the answer is (b) $\frac{283}{383}x$ .

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