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MHT CET 2026 (14 May, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2026 (14 May, Shift 1)

Q17MHT CET 2026 · 14 MAY · SHIFT 1Medium

Thermal Radiation: Black Body, Stefan & Wien

At $273^\circ$ C, the emissive power of a perfectly black body is $R$ . The value at $0^\circ$ C is

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Answer: (b)

Stefan's law: $E \propto T^4$ (T in kelvin).
$273^\circ\text{C} = 546$ K, $0^\circ\text{C} = 273$ K
$\dfrac{E'}{R} = \left(\dfrac{273}{546}\right)^4 = \dfrac{1}{16}$
So the answer is (b) $\dfrac{R}{16}$ .

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