Physics Circle home Student Login

Home›Chapters›Magnetic Properties of Materials PYQs›Earth's Magnetism›Question 2

JEE Main 2022 (29 Jun, Shift 1) · Earth's Magnetism

Earth's Magnetism question from JEE Main 2022 (29 Jun, Shift 1)

Q2JEE Main 2022 · 29 JUN · SHIFT 1Easy

Earth's Magnetism

At a certain place the angle of dip is 30∘^\circ and the horizontal component of earth's magnetic field is 0.5 G. The earth's total magnetic field (in G), at that certain place, is:

Show answer and solution

Answer: (a)

  1. H=BEcos⁡δ⇒BE=Hcos⁡30∘H = B_E\cos\delta \Rightarrow B_E = \frac{H}{\cos 30^\circ}
  2. BE=0.53/2=13 GB_E = \frac{0.5}{\sqrt{3}/2} = \frac{1}{\sqrt{3}}\ \text{G}
  3. So the answer is (a) 13\frac{1}{\sqrt{3}}.
Report a mistake

More questions on Earth's Magnetism