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MHT CET 2021 (22 Sep, Shift 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from MHT CET 2021 (22 Sep, Shift 2)

Q85MHT CET 2021 · 22 SEP · SHIFT 2Easy

Acceleration Due to Gravity

At a height 'R' above the earth's surface the gravitational acceleration is (R = radius of earth, g = acceleration due to gravity on earth's surface)

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Answer: (c)

  1. gh=g(1+h/R)2g_h = \frac{g}{(1 + h/R)^2} with h=Rh = R.
  2. gh=g22=g4g_h = \frac{g}{2^2} = \frac{g}{4}
  3. So the answer is (c) g4\frac{g}{4}.
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