Physics Circle home Student Login

Home›Chapters›Motion in One Dimension PYQs›Velocity, Acceleration & Variable Motion›Question 2

MHT CET 2025 (22 Apr, Shift 2) · Velocity, Acceleration & Variable Motion

Velocity, Acceleration & Variable Motion question from MHT CET 2025 (22 Apr, Shift 2)

Q2MHT CET 2025 · 22 APR · SHIFT 2Medium

Velocity, Acceleration & Variable Motion

At any time ' tt ', the co-ordinates of moving particle are x=at2x = at^2 and y=bt2y = bt^2. The speed of the particle is

Show answer and solution

Answer: (a)

  1. vx=dxdt=2atv_x = \dfrac{dx}{dt} = 2at, vy=dydt=2btv_y = \dfrac{dy}{dt} = 2bt
  2. Speed =(2at)2+(2bt)2=2ta2+b2= \sqrt{(2at)^2 + (2bt)^2} = 2t\sqrt{a^2 + b^2}
  3. So the answer is (a).
Report a mistake

More questions on Velocity, Acceleration & Variable Motion