At t = 0, a body of mass 100 g starts moving under the influence of a force (5i + 10j) N After 2 s its position is (2xi + 5yj) m. The ratio x: y is ______. (a) 1: 2 (b) 2: 5 (c) 5: 2 (d) 5: 4

Answer: (d). a = (5i + 10j)/(0.1) = 50i + 100j m/s² From rest: r = 1/2at² = 2(50i + 100j) = 100i + 200j 2x = 100 ⇒ x = 50; 5y = 200 ⇒ y = 40 x: y = 50: 40 = 5: 4. So the answer is (d).

At t = 0, a body of mass 100 g starts moving under the influence of a… | JEE Main 2026 (4 Apr, Shift 2)

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Inertia, First & Second Laws

At $t = 0$ , a body of mass 100 g starts moving under the influence of a force $(5\hat{i} + 10\hat{j})\text{ N}$ After 2 s its position is $(2x\hat{i} + 5y\hat{j})\text{ m}$ . The ratio $x : y$ is ______.

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Answer: (d)

$\vec{a} = \frac{5\hat{i} + 10\hat{j}}{0.1} = 50\hat{i} + 100\hat{j}\text{ m/s}^2$
From rest: $\vec{r} = \frac{1}{2}\vec{a}t^2 = 2(50\hat{i} + 100\hat{j}) = 100\hat{i} + 200\hat{j}$
$2x = 100 \Rightarrow x = 50$ ; $5y = 200 \Rightarrow y = 40$
$x : y = 50 : 40 = 5 : 4$ . So the answer is (d).

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