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JEE Main 2022 (30 Jun, Shift 1) · Horizontal Projectile & Inclined Plane

Horizontal Projectile & Inclined Plane question from JEE Main 2022 (30 Jun, Shift 1)

Q5JEE Main 2022 · 30 JUN · SHIFT 1Medium

Horizontal Projectile & Inclined Plane

At t = 0, truck, starting from rest, moves in the positive x-direction at uniform acceleration of 5 ms−2{}^{-2}. At t = 20 s, a ball is released from the top of the truck. The ball strikes the ground in 1 s after the release. The velocity of the ball, when it strikes the ground, will be:

(Given g = 10 ms−2{}^{-2})

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Answer: (a)

  1. At t=20 st = 20\text{ s}: truck speed =5×20=100 m/s= 5 \times 20 = 100\text{ m/s}, ball keeps vx=100v_x = 100.
  2. After release only gravity acts: in 1 s1\text{ s}, vy=−10×1=−10 m/sv_y = -10 \times 1 = -10\text{ m/s}.
  3. v⃗=100i^−10j^\vec{v} = 100\hat{i} - 10\hat{j}
  4. So the answer is (a).
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