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NEET 2015 (AIPMT) · Diffraction at a Single Slit

Diffraction at a Single Slit question from NEET 2015 (AIPMT)

Q80NEET 2015 · AIPMTMedium

Diffraction at a Single Slit

At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is

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Answer: (a)

At the first minimum, path difference between the two edges is $a\sin\theta = \lambda$ .
Edge and midpoint are $a/2$ apart, so their path difference is $\dfrac{\lambda}{2}$ .
Phase difference $= \dfrac{2\pi}{\lambda} \times \dfrac{\lambda}{2} = \pi$ .
So the answer is (a) $\pi$ radian.

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