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JEE Main 2022 (26 Jul, Shift 1) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from JEE Main 2022 (26 Jul, Shift 1)

Q68JEE Main 2022 · 26 JUL · SHIFT 1Easy

Biot-Savart Law & Circular Coils

$B_X$ and $B_Y$ are the magnetic fields at the centre of two coils $X$ and $Y$ respectively each carrying equal current. If coil $X$ has 200 turns and $20\text{ cm}$ radius and coil $Y$ has 400 turns and $20\text{ cm}$ radius, the ratio of $B_X$ and $B_Y$ is:

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Answer: (b)

$B = \frac{\mu_0 N I}{2r}$ ; same $I$ and $r$ , so $B \propto N$ .
$\frac{B_X}{B_Y} = \frac{200}{400} = \frac{1}{2}$
So the answer is (b) $1:2$ .

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