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JEE Main 2024 (1 Feb, Shift 2) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2024 (1 Feb, Shift 2)

Q45JEE Main 2024 · 1 FEB · SHIFT 2Easy

Electric Flux & Gauss's Law

$C_1$ and $C_2$ are two hollow concentric cubes enclosing charges $2Q$ and $3Q$ respectively as shown in figure. The ratio of electric flux passing through $C_1$ and $C_2$ is:

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Answer: (c)

Inner cube $C_1$ encloses only $2Q$ : $\phi_1 = \dfrac{2Q}{\varepsilon_0}$ .
Outer cube $C_2$ encloses $2Q + 3Q = 5Q$ : $\phi_2 = \dfrac{5Q}{\varepsilon_0}$ .
$\phi_1 : \phi_2 = 2 : 5$
So the answer is (c).

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