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JEE Main 2019 (8 Apr, Shift 2) · Resolving Power

Resolving Power question from JEE Main 2019 (8 Apr, Shift 2)

Q18JEE Main 2019 · 8 APR · SHIFT 2Easy

Resolving Power

Calculate the limit of resolution of a telescope objective having a diameter of 200 cm, if it has to detect light of wavelength 500 nm coming from a star :-

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Answer: (c)

  1. θ=1.22λD\theta = \dfrac{1.22\lambda}{D} with D=2D = 2 m, λ=500×10−9\lambda = 500\times10^{-9} m.
  2. θ=1.22×500×10−92=305×10−9\theta = \dfrac{1.22\times500\times10^{-9}}{2} = 305\times10^{-9} rad
  3. So the answer is (c) 305×10−9305\times10^{-9} radian.
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