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MHT CET 2024 (2 May, Shift 2) · Parallel Plate Capacitor

Parallel Plate Capacitor question from MHT CET 2024 (2 May, Shift 2)

Q7MHT CET 2024 · 2 MAY · SHIFT 2Easy

Parallel Plate Capacitor

Charge on a parallel plate capacitor of capacity C is Q, the electric field intensity between its two plates separated by a distance of tt is

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Answer: (b)

  1. Uniform field: E=VtE = \frac{V}{t}, and V=QCV = \frac{Q}{C}.
  2. So the answer is (b) E=QCtE = \frac{Q}{Ct}.
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