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NEET 2010 (AIPMT, Prelims) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from NEET 2010 (AIPMT, Prelims)

Q101NEET 2010 · AIPMT · PRELIMSMedium

Biot-Savart Law & Circular Coils

Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency ff Hz. The magnitude of magnetic induction at the center of the ring is

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Answer: (b)

  1. Charge qq passes any point ff times per second, so I=qfI = qf.
  2. B=μ0I2R=μ0qf2RB = \frac{\mu_0 I}{2R} = \frac{\mu_0 q f}{2R}
  3. So the answer is (b) μ0qf2R\frac{\mu_0 q f}{2R}.
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