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NEET 2011 (AIPMT, Mains) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from NEET 2011 (AIPMT, Mains)

Q100NEET 2011 · AIPMT · MAINSMedium

Biot-Savart Law & Circular Coils

Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency $f$ Hz. The magnitude of magnetic induction at the center of the ring is

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Answer: (b)

Rotating ring: $I = qf$ .
$B = \frac{\mu_0 I}{2R} = \frac{\mu_0 q f}{2R}$
So the answer is (b) $\frac{\mu_0 q f}{2R}$ .

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