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MHT CET 2026 (13 May, Shift 2) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from MHT CET 2026 (13 May, Shift 2)

Q11MHT CET 2026 · 13 MAY · SHIFT 2Medium

Electric Charge & Coulomb's Law

Charge q2q_2 of mass 'mm' revolves around a stationary charge q1q_1 in a circular orbit of radius 'rr'. The orbital periodic time of q2q_2 would be (k=14πϵ0)\left(k = \frac{1}{4\pi\epsilon_0}\right)

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Answer: (a)

  1. Coulomb force gives centripetal force: kq1q2r2=mω2r=4π2mrT2\dfrac{kq_1q_2}{r^2} = m\omega^2 r = \dfrac{4\pi^2 m r}{T^2}.
  2. T2=4π2mr3kq1q2T^2 = \dfrac{4\pi^2 m r^3}{kq_1q_2}
  3. So the answer is (a) T=[4π2mr3kq1q2]1/2T = \left[\dfrac{4\pi^2 m r^3}{kq_1q_2}\right]^{1/2}.
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