Physics Circle home Student Login

Home›Chapters›Electrostatics PYQs›Electric Dipole›Question 66

JEE Main 2019 (10 Jan, Shift 2) · Electric Dipole

Electric Dipole question from JEE Main 2019 (10 Jan, Shift 2)

Q66JEE Main 2019 · 10 JAN · SHIFT 2Medium

Electric Dipole

Charges –q and +q located at A and B, respectively, constitude an electric dipole. Distance AB = 2a, O is the mid point of the dipole and OP is perpendicular to AB. A charge Q is placed at P where OP = y and y >> 2a. The charge Q experiences an electrostatic force F. If Q is now moved along the equatorial line to P' such that OP' = (y3)\left(\frac{y}{3}\right), the force on Q will be close to - (y3≫2a)\left(\frac{y}{3} \gg 2a\right)

Figure

Show answer and solution

Answer: (d)

  1. Far on the equatorial line E=kpy3E = \frac{kp}{y^3}, so F=QE∝1y3F = QE \propto \frac{1}{y^3}.
  2. y→y3y \to \frac{y}{3}: F′=33F=27FF' = 3^3 F = 27F
  3. So the answer is (d) 27F27F.
Report a mistake

More questions on Electric Dipole