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JEE Main 2023 (30 Jan, Shift 1) · Shear Modulus & Poisson's Ratio

Shear Modulus & Poisson's Ratio question from JEE Main 2023 (30 Jan, Shift 1)

Q5JEE Main 2023 · 30 JAN · SHIFT 1Easy

Shear Modulus & Poisson's Ratio

Choose the correct relationship between Poisson ratio (σ)(\sigma), bulk modulus (K) and modulus of rigidity (η)(\eta) of a given solid object:

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Answer: (b)

  1. Y=3K(1−2σ)Y = 3K(1-2\sigma) and Y=2η(1+σ)Y = 2\eta(1+\sigma)
  2. Equate: 3K−6Kσ=2η+2ησ3K - 6K\sigma = 2\eta + 2\eta\sigma
  3. σ(6K+2η)=3K−2η⇒σ=3K−2η6K+2η\sigma(6K + 2\eta) = 3K - 2\eta \Rightarrow \sigma = \frac{3K-2\eta}{6K+2\eta}
  4. So the answer is (b).
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