Choose the correct statement for processes A & B shown in figure. (a) PV = k for process B and A. (b) Pγ-1Tγ = k for process B and T = k for process A. (c) TγPγ-1 = k for process A and PV = k for process B. (d) PVγ = k for process B and PV = k for process A.

Answer: (b). Adiabatic curve is steeper than an isotherm, so B is adiabatic and A is isothermal ( T = k). Adiabatic: PVγ = k with V ∝ T/P gives P1-γTγ = k, i.e. Pγ - 1Tγ = k. So the answer is (b).

Choose the correct statement for processes A & B shown in figure. | JEE Main 2024 (30 Jan, Shift 2 (one Or More Correct))

Q32JEE Main 2024 · 30 JAN · SHIFT 2 (One or more correct)Medium

P-V Diagrams & Cyclic Processes

Choose the correct statement for processes A & B shown in figure.

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Answer: (b)

Adiabatic curve is steeper than an isotherm, so B is adiabatic and A is isothermal ( $T = k$ ).
Adiabatic: $PV^\gamma = k$ with $V \propto T/P$ gives $P^{1-\gamma}T^\gamma = k$ , i.e. $\frac{P^{\gamma - 1}}{T^\gamma} = k$ .
So the answer is (b).

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P-V Diagrams & Cyclic Processes question from JEE Main 2024 (30 Jan, Shift 2 (one Or More Correct))

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