Combination of four parallel plate air capacitors is shown in figure. Separation between the plate P₁ & P₂ is d/3 and separation between the plates P₂ and P₃ is d. The equivalent capacitance of the configuration is _______. (Given (ε₀ A)/(d) = 4. Where A=Area of plates) Numerical answer type. Work it out, then open the answer.

Answer: 3. Between P₁ and P₂ the three parts ( A/6, A/3, A/2) are in parallel, total area A, gap d/3: C₁ = (3ε₀ A)/(d) = 12. Between P₂ and P₃: C₂ = (ε₀ A)/(d) = 4. In series: C = (12× 4)/(16) = 3 Answer: 3 μ F

Combination of four parallel plate air capacitors is shown in figure… | JEE Main 2022 (30 Jul, Shift 2)

Q57JEE Main 2022 · 30 JUL · SHIFT 2Medium

Combination of Capacitors

Combination of four parallel plate air capacitors is shown in figure. Separation between the plate $P_1$ & $P_2$ is $\frac{d}{3}$ and separation between the plates $P_2$ and $P_3$ is $d$ . The equivalent capacitance of the configuration is _______ $\mu\text{F}$ .

(Given $\frac{\epsilon_0 A}{d} = 4\ \mu\text{F}$ . Where A=Area of plates)

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 3

Between $P_1$ and $P_2$ the three parts ( $A/6$ , $A/3$ , $A/2$ ) are in parallel, total area $A$ , gap $d/3$ : $C_1 = \frac{3\epsilon_0 A}{d} = 12\ \mu\text{F}$ .
Between $P_2$ and $P_3$ : $C_2 = \frac{\epsilon_0 A}{d} = 4\ \mu\text{F}$ .
In series: $C = \frac{12\times 4}{16} = 3\ \mu\text{F}$
Answer: 3 $\mu$ F

Report a mistake

Combination of Capacitors question from JEE Main 2022 (30 Jul, Shift 2)

More questions on Combination of Capacitors