Complete the equation for the following fission process: ₉₂U²³⁵ + ₀n¹ ₃₈Sr⁹⁰ + (a) ₅₄Xe¹⁴³ + 3 ₀n¹ (b) ₅₄Xe¹⁴⁵ (c) ₅₇Xe¹⁴² (d) ₅₄Xe¹⁴² + ₀n¹

Answer: (a). Left side: A = 235 + 1 = 236, Z = 92. After Sr: A = 236 - 90 = 146, Z = 92 - 38 = 54. (a) ₅₄Xe¹⁴³ + 3 n: A = 146, Z = 54, balanced. So the answer is (a).

Complete the equation for the following fission process: ₉₂U²³⁵ + ₀n¹… | NEET 1998 (AIPMT)

Q40NEET 1998 · AIPMTEasy

Nuclear Fission & Fusion

Complete the equation for the following fission process:

${}_{92}\text{U}^{235} + {}_{0}n^{1} \longrightarrow {}_{38}\text{Sr}^{90} + \ldots\ldots$

Show answer and solution

Answer: (a)

Left side: $A = 235 + 1 = 236$ , $Z = 92$ .
After Sr: $A = 236 - 90 = 146$ , $Z = 92 - 38 = 54$ .
(a) ${}_{54}\text{Xe}^{143} + 3\,n$ : $A = 146$ , $Z = 54$ , balanced.
So the answer is (a).

Report a mistake

Nuclear Fission & Fusion question from NEET 1998 (AIPMT)

More questions on Nuclear Fission & Fusion