Physics Circle home Student Login

Home›Chapters›Semiconductor Electronics PYQs›P-N Junction Diode›Question 21

JEE Main 2026 (4 Apr, Shift 1) · P-N Junction Diode

P-N Junction Diode question from JEE Main 2026 (4 Apr, Shift 1)

Q21JEE Main 2026 · 4 APR · SHIFT 1Difficult

P-N Junction Diode

Consider a circuit consisting of a capacitor (20 μF)(20\,\mu\text{F}), resistor (100 Ω)(100\,\Omega) and two identical diodes as shown in figure. The resistance of diode under forward biasing condition is 10 Ω10\,\Omega. The time constant of the circuit is α×10−3 s\alpha \times 10^{-3}\text{ s}. The value of α\alpha is ______

Figure

Show answer and solution

Answer: (a)

  1. The two diodes are in parallel but opposite, so for either current direction exactly one is forward biased (10 Ω10\ \Omega) and the other is open.
  2. Total resistance in series with CC: R=100+10=110 ΩR = 100 + 10 = 110\ \Omega.
  3. τ=RC=110×20×10−6=2.2×10−3\tau = RC = 110 \times 20 \times 10^{-6} = 2.2 \times 10^{-3} s.
  4. So α=2.2\alpha = 2.2, answer (a).
Report a mistake

More questions on P-N Junction Diode