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JEE Main 2025 (23 Jan, Shift 1) · Composite & Cut-Out Bodies

Composite & Cut-Out Bodies question from JEE Main 2025 (23 Jan, Shift 1)

Q4JEE Main 2025 · 23 JAN · SHIFT 1Medium

Composite & Cut-Out Bodies

Consider a circular disc of radius 20 cm with centre located at the origin. A circular hole of radius 5 cm is cut from this disc in such a way that the edge of the hole touches the edge of the disc. The distance of centre of mass of residual or remaining disc from the origin will be

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Answer: (d)

  1. Hole touches the edge, so its centre is at 20−5=1520 - 5 = 15 cm from O. Mass ∝\propto area ∝r2\propto r^2.
  2. Disc: 202=40020^2 = 400 units at x=0x=0; hole: 52=255^2 = 25 units at x=15x = 15 cm.
  3. xcm=400(0)−25(15)400−25=−375375=−1x_{cm} = \frac{400(0) - 25(15)}{400-25} = -\frac{375}{375} = -1 cm
  4. So the answer is (d) 1.01.0 cm (on the side opposite the hole).
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