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MHT CET 2026 (19 May, Shift 2) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from MHT CET 2026 (19 May, Shift 2)

Q14MHT CET 2026 · 19 MAY · SHIFT 2Medium

Biot-Savart Law & Circular Coils

Consider a circular loop (radius RR) carrying current II, the magnetic field produced by it at a point on the axis at a distance zz from the centre of the loop is xR2(z2+R2)3/2\frac{xR^2}{(z^2+R^2)^{3/2}}. The value of xx is

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Answer: (c)

  1. Field on the axis of a loop: B=μ0IR22(z2+R2)3/2B = \frac{\mu_0 I R^2}{2(z^2 + R^2)^{3/2}}.
  2. Comparing with xR2(z2+R2)3/2\frac{x R^2}{(z^2 + R^2)^{3/2}} gives x=μ0I2x = \frac{\mu_0 I}{2}.
  3. So the answer is (c) μ0I2\frac{\mu_0 I}{2}.
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