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JEE Main 2025 (2 Apr, Shift 2) · Electric Field & Field Lines

Electric Field & Field Lines question from JEE Main 2025 (2 Apr, Shift 2)

Q10JEE Main 2025 · 2 APR · SHIFT 2Medium

Electric Field & Field Lines

Consider a circular loop that is uniformly charged and has a radius $a\sqrt{2}$ . Find the position along the positive $z$ -axis of the cartesian coordinate system where the electric field is maximum if the ring was assumed to be placed in $xy$ plane at the origin:

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Answer: (a)

On the axis of a ring: $E = \dfrac{kQz}{(z^2+R^2)^{3/2}}$ ; setting $\dfrac{dE}{dz} = 0$ gives $z = \dfrac{R}{\sqrt{2}}$ .
Here $R = a\sqrt{2}$ , so $z = \dfrac{a\sqrt{2}}{\sqrt{2}} = a$ .
So the answer is (a) $a$ .

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