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JEE Main 2020 (3 Sep, Shift 1) · Degrees of Freedom & Internal Energy

Degrees of Freedom & Internal Energy question from JEE Main 2020 (3 Sep, Shift 1)

Q29JEE Main 2020 · 3 SEP · SHIFT 1Medium

Degrees of Freedom & Internal Energy

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Consider a gas of triatomic molecules. The molecules are assumed to be triangular and made of massless rigid rods whose vertices are occupied by atoms. The internal energy of a mole of the gas at temperature T is:

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Answer: (d)

  1. A rigid triangular (non-linear) molecule: 3 translational + 3 rotational, no vibration, so f=6f = 6.
  2. U=f2RT=62RTU = \frac{f}{2}RT = \frac{6}{2}RT per mole
  3. So the answer is (d) 3RT3RT.
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