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MHT CET 2024 (15 May, Shift 1) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from MHT CET 2024 (15 May, Shift 1)

Q52MHT CET 2024 · 15 MAY · SHIFT 1Medium

Electric Flux & Gauss's Law

Consider a long uniformly charged cylinder having constant volume charge density ' $\lambda$ ' and radius ' $R$ '. A Gaussian surface is in the form of a cylinder of radius ' $r$ ' such that vertical axis of both the cylinders coincide. For a point inside the cylinder $(r < R)$ , electric field is directly proportional to

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Answer: (b)

Gaussian cylinder of radius $r < R$ and length $l$ : $E(2\pi rl) = \frac{\rho\pi r^2l}{\varepsilon_0}$ .
$E = \frac{\rho r}{2\varepsilon_0}$ , so $E \propto r$ .
So the answer is (b) $r$ .

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