Consider a mixture of gas molecule of types A, B and C having masses mA 1/vB > 1/vC (c) 1/vA < 1/vB < 1/vC (d) vA = vB = vC = 0

Answer: (c). At the same temperature vrms ∝ 1/√(m). mA vB > vC Taking reciprocals: 1/vA < 1/vB < 1/vC So the answer is (c).

Consider a mixture of gas molecule of types A, B and C having masses… | JEE Main 2021 (20 Jul, Shift 1)

Q65JEE Main 2021 · 20 JUL · SHIFT 1Easy

Molecular Speeds & Maxwell Distribution

Consider a mixture of gas molecule of types A, B and C having masses mA < mB < mC. The ratio of their root mean square speeds at normal temperature and pressure is:

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Answer: (c)

At the same temperature $v_{rms} \propto \frac{1}{\sqrt{m}}$ .
$m_A < m_B < m_C \Rightarrow v_A > v_B > v_C$
Taking reciprocals: $\frac{1}{v_A} < \frac{1}{v_B} < \frac{1}{v_C}$
So the answer is (c).

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Molecular Speeds & Maxwell Distribution question from JEE Main 2021 (20 Jul, Shift 1)

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