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JEE Main 2026 (21 Jan, Shift 1) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from JEE Main 2026 (21 Jan, Shift 1)

Q5JEE Main 2026 · 21 JAN · SHIFT 1Easy

Applications of Dimensional Analysis

Consider a modified Bernoulli equation.

(P+ABt2)+ρg(h+Bt)+12ρV2=\left(\mathrm{P} + \frac{A}{Bt^2}\right) + \rho g(h + Bt) + \frac{1}{2}\rho V^2 = constant

If tt has the dimension of time then the dimensions of AA and BB are ______ respectively.

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Answer: (d)

  1. BtBt is added to hh: [B]=[L]/[T]=[M0LT−1][B] = [L]/[T] = [M^0LT^{-1}].
  2. ABt2\frac{A}{Bt^2} is added to PP: [A]=[P][B][T2]=[ML−1T−2][LT−1][T2][A] = [P][B][T^2] = [ML^{-1}T^{-2}][LT^{-1}][T^2].
  3. [A]=[ML0T−1][A] = [ML^0T^{-1}].
  4. So the answer is (d).
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