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JEE Main 2015 · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2015

Q227JEE Main 2015Difficult

Thermodynamic Processes

Consider a spherical shell of radius RR at temperature TT. The black body radiation inside it can be considered as an ideal gas of photons with internal energy per unit volume u=UV∝T4u = \frac{U}{V} \propto T^{4} and pressure p=13(UV)p = \frac{1}{3}\left(\frac{U}{V}\right). If the shell now undergoes an adiabatic expansion the relation between TT and RR is:

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Answer: (a)

  1. Adiabatic: dU=−p dVdU = -p\,dV, with U=aT4VU = aT^4V and p=13aT4p = \frac{1}{3}aT^4.
  2. 4aT3V dT+aT4 dV=−13aT4 dV⇒dTT=−13dVV4aT^3V\,dT + aT^4\,dV = -\frac{1}{3}aT^4\,dV \Rightarrow \frac{dT}{T} = -\frac{1}{3}\frac{dV}{V}
  3. So T∝V−1/3T \propto V^{-1/3}, and V∝R3V \propto R^3 gives T∝1RT \propto \frac{1}{R}.
  4. So the answer is (a).
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