Consider a spring-mass simple harmonic oscillator in one dimension… | NEET 2026 (Re-neet)

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Velocity & Acceleration in SHM

Consider a spring-mass simple harmonic oscillator in one dimension. The mass of the particle is $m\text{ kg}$ and the spring constant is $k\text{ N m}^{-1}$ . At a given instant, the extension of the spring is $x$ -meter and the speed of the particle is $v\text{ m s}^{-1}$ . On the $x - v$ plane, if the graph of $v$ as a function of $x$ is a circle, then the correct option is:

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Answer: (c)

$v^2 = \frac{k}{m}(A^2 - x^2) \Rightarrow v^2 + \frac{k}{m}x^2 = \frac{k}{m}A^2$ .
This is a circle only if the coefficients of $x^2$ and $v^2$ are equal: $\frac{k}{m} = 1$ .
So the answer is (c) $k = m$ .

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