Physics Circle home Student Login

Home›Chapters›Centre of Mass PYQs›Centre of Mass of Discrete Particles›Question 23

NEET 2004 (AIPMT) · Centre of Mass of Discrete Particles

Centre of Mass of Discrete Particles question from NEET 2004 (AIPMT)

Q23NEET 2004 · AIPMTEasy

Centre of Mass of Discrete Particles

Consider a system of two particles having masses m1 and m2. If the particle of mass m1 is pushed towards the mass centre of particles through a distance d. by what distance would be particle of mass m2 move so as to keep the mass centre of particles at the original position?

Show answer and solution

Answer: (b)

  1. CM unchanged: m1Δx1+m2Δx2=0m_1 \Delta x_1 + m_2 \Delta x_2 = 0, so the displacements are opposite and m1d=m2d2m_1 d = m_2 d_2.
  2. d2=m1m2dd_2 = \frac{m_1}{m_2} d (towards the CM)
  3. So the answer is (b) m1m2d\frac{m_1}{m_2} d.
Report a mistake

More questions on Centre of Mass of Discrete Particles