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JEE Main 2006 (AIEEE) · Centre of Mass of Discrete Particles

Centre of Mass of Discrete Particles question from JEE Main 2006 (AIEEE)

Q22JEE Main 2006 · AIEEEEasy

Centre of Mass of Discrete Particles

Consider a two particle system with particles having masses $m_1$ and $m_2$ . If the first particle is pushed towards the center of mass through a distance $d,$ by what distance should the second particle is moved, so as to keep the center of mass at the same position?

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Answer: (c)

CM unchanged: $m_1 \Delta x_1 + m_2 \Delta x_2 = 0 \Rightarrow m_1 d = m_2 d_2$
$d_2 = \frac{m_1}{m_2} d$ (towards the CM)
So the answer is (c) $\frac{m_1}{m_2} d$ .

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