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JEE Main 2008 (AIEEE) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from JEE Main 2008 (AIEEE)

Q187JEE Main 2008 · AIEEEEasy

Moment of Inertia & Radius of Gyration

Consider a uniform square plate of side $\text{'}a\text{'}$ and mass $\text{'}m\text{'}$ . The moment of inertia of this plate about an axis perpendicular to its plane and passing through one of its corners is

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Answer: (d)

Central normal axis: $I_{cm} = \frac{m(a^2+a^2)}{12} = \frac{ma^2}{6}$ .
Corner distance $d^2 = \frac{a^2}{2}$ , so $I = \frac{ma^2}{6} + \frac{ma^2}{2}$ .
So the answer is (d) $\frac{2}{3}ma^2$ .

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