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JEE Main 2008 (AIEEE) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from JEE Main 2008 (AIEEE)

Q187JEE Main 2008 · AIEEEEasy

Moment of Inertia & Radius of Gyration

Consider a uniform square plate of side ’a’\text{'}a\text{'} and mass ’m’\text{'}m\text{'}. The moment of inertia of this plate about an axis perpendicular to its plane and passing through one of its corners is

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Answer: (d)

  1. Central normal axis: Icm=m(a2+a2)12=ma26I_{cm} = \frac{m(a^2+a^2)}{12} = \frac{ma^2}{6}.
  2. Corner distance d2=a22d^2 = \frac{a^2}{2}, so I=ma26+ma22I = \frac{ma^2}{6} + \frac{ma^2}{2}.
  3. So the answer is (d) 23ma2\frac{2}{3}ma^2.
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