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JEE Main 2025 (29 Jan, Shift 1) · Mutual Inductance

Mutual Inductance question from JEE Main 2025 (29 Jan, Shift 1)

Q23JEE Main 2025 · 29 JAN · SHIFT 1Medium

Mutual Inductance

Consider I1 and I2 are the currents flowing simultaneously in two nearby coils 1 & 2, respectively. If L1 = self inductance of coil 1, M12 = mutual inductance of coil 1 with respect to coil 2, then the value of induced emf in coil 1 will be:

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Answer: (d)

Total flux linked with coil 1: $\Phi_1 = L_1I_1 + M_{12}I_2$
$e_1 = -\dfrac{d\Phi_1}{dt} = -L_1\dfrac{dI_1}{dt} - M_{12}\dfrac{dI_2}{dt}$
So the answer is (d).

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