Consider light travelling from a medium A to medium B separated by a… | JEE Main 2026 (23 Jan, Shift 1)

Q2JEE Main 2026 · 23 JAN · SHIFT 1Easy

Total Internal Reflection

Consider light travelling from a medium $A$ to medium $B$ separated by a plane interface. If the light undergoes total internal reflection during its travel from medium $A$ to $B$ and the speed of light in media $A$ and $B$ are $2.4 \times 10^{8}\text{ m/s}$ and $2.7 \times 10^{8}\text{ m/s}$ , respectively, then the value of critical angle is:

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Answer: (d)

$\sin C = \frac{\mu_B}{\mu_A} = \frac{v_A}{v_B} = \frac{2.4}{2.7} = \frac{8}{9}$ .
$\cos C = \sqrt{1 - \frac{64}{81}} = \frac{\sqrt{17}}{9}$
$\tan C = \frac{8/9}{\sqrt{17}/9} = \frac{8}{\sqrt{17}}$
So the answer is (d) $\tan^{-1}\left(\frac{8}{\sqrt{17}}\right)$ .

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Total Internal Reflection question from JEE Main 2026 (23 Jan, Shift 1)

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