Consider the following circuit. By keeping S₁ closed, the capacitor is fully charged and then S₁ is opened and S₂ is closed, then (a) At time t = 0, the energy stored in the circuit is purely in the form of magnetic energy. (b) At t > 0, there is no exchange of energy between L and C. (c) At any time t > 0, the current in the circuit is in the same direction. (d) At any time t > 0, the instantaneous current in the circuit may be V√(C/L)

Answer: (d). At t = 0 the capacitor holds charge CV and the current is zero, so all energy is electric: (a) is false. Energy keeps passing back and forth between C and L (LC oscillation): (b) is false. The current is sinusoidal, so it reverses direction every half cycle: (c) is false. Maximum current from 1/2CV² = 1/2LI₀²: I₀ = V√(C/L), which the current reaches at some instants. So the answer is (d).

Consider the following circuit. By keeping S₁ closed, the capacitor… | MHT CET 2024 (9 May, Shift 2)

Q19MHT CET 2024 · 9 MAY · SHIFT 2Medium

Combination of Inductors, LR & LC Circuits

Consider the following circuit. By keeping $S_1$ closed, the capacitor is fully charged and then $S_1$ is opened and $S_2$ is closed, then

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Answer: (d)

At $t = 0$ the capacitor holds charge $CV$ and the current is zero, so all energy is electric: (a) is false.
Energy keeps passing back and forth between $C$ and $L$ (LC oscillation): (b) is false.
The current is sinusoidal, so it reverses direction every half cycle: (c) is false.
Maximum current from $\frac{1}{2}CV^2 = \frac{1}{2}LI_0^2$ : $I_0 = V\sqrt{C/L}$ , which the current reaches at some instants.
So the answer is (d).

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Combination of Inductors, LR & LC Circuits question from MHT CET 2024 (9 May, Shift 2)

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