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NEET 2026 (Re-neet) · Refraction, Glass Slab & Apparent Depth

Refraction, Glass Slab & Apparent Depth question from NEET 2026 (Re-neet)

Q8NEET 2026 · RE-NEETMedium

Refraction, Glass Slab & Apparent Depth

Consider three media P,QP, Q and RR with refractive indices 1,1.251, 1.25, and 1.5 respectively. The medium QQ having a thickness of 5 cm is placed between extended media PP and RR as shown in the figure. An object OO is placed at the centre of medium QQ. If viewed from medium PP near the normal direction, the apparent depth of OO is h1h_1. For similar observation from medium RR, the apparent depth is h2h_2. The value of ∣h1−h2∣|h_1 - h_2|, in cm, is:

Figure

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Answer: (c)

  1. OO is at the centre, 2.52.5 cm from each face of QQ.
  2. Seen from PP: h1=2.5×nPnQ=2.5×11.25=2h_1 = 2.5 \times \dfrac{n_P}{n_Q} = 2.5 \times \dfrac{1}{1.25} = 2 cm.
  3. Seen from RR: h2=2.5×nRnQ=2.5×1.51.25=3h_2 = 2.5 \times \dfrac{n_R}{n_Q} = 2.5 \times \dfrac{1.5}{1.25} = 3 cm.
  4. ∣h1−h2∣=1|h_1 - h_2| = 1 cm, so the answer is (c).
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