Consider two coils in which a current in one coil carrying 6 A causes the change in the flux in the second coil 12 × 10⁻⁴ weber/turn. The second coil has 2000 turns. The mutual inductance between the coils is (a) 0.2 H (b) 0.3 H (c) 0.4 H (d) 2.4 H

Answer: (c). M = (N₂ φ₂)/(I₁) M = 2000 × 12× 10⁻⁴6 = 2.4/6 = 0.4 H So the answer is (c) 0.4 H.

Consider two coils in which a current in one coil carrying 6 A causes… | MHT CET 2026 (19 Apr, Shift 1)

Q3MHT CET 2026 · 19 APR · SHIFT 1Easy

Mutual Inductance

Consider two coils in which a current in one coil carrying $6$ A causes the change in the flux in the second coil $12 \times 10^{-4}$ weber/turn. The second coil has $2000$ turns. The mutual inductance between the coils is

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Answer: (c)

$M = \dfrac{N_2 \phi_2}{I_1}$
$M = \dfrac{2000 \times 12\times 10^{-4}}{6} = \dfrac{2.4}{6} = 0.4$ H
So the answer is (c) $0.4$ H.

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Mutual Inductance question from MHT CET 2026 (19 Apr, Shift 1)

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