Consider two rods 1 and 2 of same length. They have different specific heats (C₁, C₂), thermal conductivities (K₁, K₂) and area of cross-section (A₁, A₂) respectively. Both the rods have temperatures (T₁, T₂) at their ends. If their rate of loss of heat due to conduction is equal, then (a) A₁K₂ = A₂K₁ (b) A₁K₁ = A₂K₂ (c) (A₁K₁)/(C₁) = (A₂K₂)/(C₂) (d) (A₁K₂)/(C₁) = (A₂K₁)/(C₂)

Answer: (b). Conduction rate H = (KAΔ T)/(L) does not involve specific heat. Same L and Δ T: H₁ = H₂ ⇒ A₁K₁ = A₂K₂ So the answer is (b).

Consider two rods 1 and 2 of same length. They have different… | MHT CET 2026 (17 Apr, Shift 1)

Q9MHT CET 2026 · 17 APR · SHIFT 1Medium

Heat Conduction

Consider two rods 1 and 2 of same length. They have different specific heats $(C_1, C_2)$ , thermal conductivities $(K_1, K_2)$ and area of cross-section $(A_1, A_2)$ respectively. Both the rods have temperatures $(T_1, T_2)$ at their ends. If their rate of loss of heat due to conduction is equal, then

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Answer: (b)

Conduction rate $H = \frac{KA\Delta T}{L}$ does not involve specific heat.
Same $L$ and $\Delta T$ : $H_1 = H_2 \Rightarrow A_1K_1 = A_2K_2$
So the answer is (b).

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Heat Conduction question from MHT CET 2026 (17 Apr, Shift 1)

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