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JEE Main 2020 (8 Jan, Shift 1) · Gravitational Field

Gravitational Field question from JEE Main 2020 (8 Jan, Shift 1)

Q9JEE Main 2020 · 8 JAN · SHIFT 1Medium

Gravitational Field

Consider two solid spheres of radii R1 = 1m, R2 = 2m and masses M1 and M2, respectively. The gravitational field due to sphere (1) and (2) are shown. The value of $\frac{M_1}{M_2}$ is:

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Answer: (b)

The peak of each graph is the surface field $E = \frac{GM}{R^2}$ .
Sphere 1: $\frac{GM_1}{1^2} = 2 \Rightarrow GM_1 = 2$ .
Sphere 2: $\frac{GM_2}{2^2} = 3 \Rightarrow GM_2 = 12$ .
$\frac{M_1}{M_2} = \frac{2}{12} = \frac{1}{6}$
So the answer is (b) $\frac{1}{6}$ .

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