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JEE Main 2025 (4 Apr, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from JEE Main 2025 (4 Apr, Shift 1)

Q33JEE Main 2025 · 4 APR · SHIFT 1Easy

Bohr Model: Orbits, Speed & Angular Momentum

Considering the Bohr model of hydrogen like atoms, the ratio of the radius of 55th orbit of the electron in Li2+\text{Li}^{2+} and He+\text{He}^{+}is

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Answer: (b)

  1. rn=n2a0Zr_n = \dfrac{n^2 a_0}{Z}; same n=5n = 5, so r∝1Zr \propto \dfrac{1}{Z}.
  2. rLi2+rHe+=ZHeZLi=23\dfrac{r_{\text{Li}^{2+}}}{r_{\text{He}^+}} = \dfrac{Z_{\text{He}}}{Z_{\text{Li}}} = \dfrac{2}{3}
  3. So the answer is (b).
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